4[x-3(x-2)]+1=5

Solution for 4[x-3(x-2)]+1=5 equation:

Simplifying
4[x + -3(x + -2)] + 1 = 5

Reorder the terms:
4[x + -3(-2 + x)] + 1 = 5
4[x + (-2 * -3 + x * -3)] + 1 = 5
4[x + (6 + -3x)] + 1 = 5

Reorder the terms:
4[6 + x + -3x] + 1 = 5

Combine like terms: x + -3x = -2x
4[6 + -2x] + 1 = 5
[6 * 4 + -2x * 4] + 1 = 5
[24 + -8x] + 1 = 5

Reorder the terms:
24 + 1 + -8x = 5

Combine like terms: 24 + 1 = 25
25 + -8x = 5

Solving
25 + -8x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-25' to each side of the equation.
25 + -25 + -8x = 5 + -25

Combine like terms: 25 + -25 = 0
0 + -8x = 5 + -25
-8x = 5 + -25

Combine like terms: 5 + -25 = -20
-8x = -20

Divide each side by '-8'.
x = 2.5

Simplifying
x = 2.5